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Peroxide effects is observed only in HBr and not in HCl or Hl.Justify. |
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Answer» Solution :`CH_(3)-CH=CH_(2)+HBroverset("Peroxide")underset((C_(6)H_(5)CO)_(2)O_(2))(to)CH_(3)-CH_(2)-CH_(2)-Br` The `H-Cl` bond is STRONGER `(430.5 kJ mol^(-1))` than `H-Br` bond `(363.7kJmol^(-1))`, thus `H-Cl` is not cleaved by the free radical. The `H-I` bond is weaker `(296.8kJ mol^(-1))` , than `H-Cl` bond. US `H-I` bond BREAKS easily but IODINE free radicals combine to form iodine molecules instead of adding to the double bond and hence peroxide effect is not observed in `HCl` & `HI`. |
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