1.

Peroxide ion …… (i) has five completely filled antibonding molecular orbitals (ii) is diamagnetic "" (iii) has bond order one (iv) is isoelectronic with neon Which of these are correct ?

Answer»

(III) and (iv)
(i) , (ii) and (v)
(ii) and (iii)
(i) and (v)

Solution :PEROXIDE ion is `O_(2)^(2-)`
E.C. `sigma_(1s)^(2) sigma_(1s)^(**2)sigma_(2s)^(2)sigma_(2s)^(**2)sigma_(2p_(z))^(2)pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**2)pi_(2p_(y))^(**2)`
It tha four completely filled antibonding molecular
obitals . It is diamgnetic .
Bond order `= (1)/(2) (10 - 8) = 1`
Total electrons PRESENT = 18
Thus , it is not isoelectronic with neon `._ ""(10)Ne`
Hence, only option (ii) and (iii) are correct


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