1.

Peter requires 50% to pass. If he gets 280 marks and falls short by 20 marks, what would have been the maximum marks of the exam?

Answer»

Peters score = 280 marks 

Marks needed for a pass = 20 

∴ Total marks required to get a pass = 280 + 20 

= 300 

i.e. 50% of total marks = 300 

\(\frac{50}{100}\) x Total marks = 300  

\(\frac{1}{2}\) x Total Marks = 300

Total Marks = 300 x 2 

= 600 

Total marks of the exam = 600



Discussion

No Comment Found