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Peter requires 50% to pass. If he gets 280 marks and falls short by 20 marks, what would have been the maximum marks of the exam? |
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Answer» Peters score = 280 marks Marks needed for a pass = 20 ∴ Total marks required to get a pass = 280 + 20 = 300 i.e. 50% of total marks = 300 \(\frac{50}{100}\) x Total marks = 300 \(\frac{1}{2}\) x Total Marks = 300 Total Marks = 300 x 2 = 600 Total marks of the exam = 600 |
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