फ्। 3 23 dan 4C A 3$९९ ने७

1.	फ्। 3 23 dan 4C A 3$९९ ने७
Answer» (tan20/cosec70)^2 + (cot20/sec70)^2 + 2tan15tan45tan75 ={tan(90-20)/cosec70}^2 + {cot90-20)/sec70}^2 + 2(tan90-15)tan45 tan 75 =(cot70/cosec70)^2 + (tan70/sec70) ^2+ 2(cot75 tan 45 tan75 ) =(cos 70/sin70/1/sin70)^2 +(sin70/cos70/1/cos70) ^2 + 2(1×1) =(cos70+sin70)^2 +2 =1+2 =3 Hit like if you find it useful!

Answer»

(tan20/cosec70)^2 + (cot20/sec70)^2 + 2tan15tan45tan75

={tan(90-20)/cosec70}^2 + {cot90-20)/sec70}^2 + 2(tan90-15)tan45 tan 75

=(cot70/cosec70)^2 + (tan70/sec70) ^2+ 2(cot75 tan 45 tan75 )

=(cos 70/sin70/1/sin70)^2 +(sin70/cos70/1/cos70) ^2 + 2(1×1)

=(cos70+sin70)^2 +2

=1+2

Hit like if you find it useful!

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