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Ph-C≡ C-CH_3 \xrightarrow[{H_2SO_4}]{HgSO_4}A , A is (1) Ph-CH_2-\underset{\overset\parallel{\underset{}O} }C - CH_{3 }(2) Ph-\underset{\underset O\parallel}C -CH_2-CH_3 (3) Ph- \underset{\underset{OH}l}{CH}- CH_2-CH_3 (4) Ph-CH_2-\underset{\underset{OH}l}{CH }-CH_{ |
| Answer» Ph-C≡ C-CH_3 \xrightarrow[{H_2SO_4}]{HgSO_4}A , A is (1) Ph-CH_2-\underset{\overset\parallel{\underset{}O} }C - CH_{3 }(2) Ph-\underset{\underset O\parallel}C -CH_2-CH_3 (3) Ph- \underset{\underset{OH}l}{CH}- CH_2-CH_3 (4) Ph-CH_2-\underset{\underset{OH}l}{CH }-CH_{ | |