pH is the negative logarithm of `H^(+)`` pH=log[H^(+)]` `HCl lt H^(+)+Cl^(-)` `H_(2)OhArrH^(+)+OH^(-)` ` K_(W)=[H^(+)][OH^(-)]` `K_(W)` depend on the temperatue. With rise in temperature `K_(W)` increases. At 298 K, pH of pure water = 7 The pH at first equivalance of `H_(3)PO_(4)` vs NaOH will beA. 7B. `gt7`C. `lt7`D. Depend on the concentration of titrant

pH is the negative logarithm of `H^(+)`` pH=log[H^(+)]` `HCl lt H^(+)+

1.	pH is the negative logarithm of `H^(+)`` pH=log[H^(+)]` `HCl lt H^(+)+Cl^(-)` `H_(2)OhArrH^(+)+OH^(-)` ` K_(W)=[H^(+)][OH^(-)]` `K_(W)` depend on the temperatue. With rise in temperature `K_(W)` increases. At 298 K, pH of pure water = 7 The pH at first equivalance of `H_(3)PO_(4)` vs NaOH will beA. 7B. `gt7`C. `lt7`D. Depend on the concentration of titrant
Answer» Correct Answer - C

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