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pH is the negative logarithm of `H^(+)`` pH=log[H^(+)]` `HCllt H^(+)+Cl^(-)` `H_(2)OhArrH^(+)+OH^(-)` ` K_(W)=[H^(+)][OH^(-)]` `K_(W)` depend on the temperatue. With rise in temperature `K_(W)` increases. At 298 K, pH of pure water = 7 The exact concentration of `H^(+)` in `10^(-6)` M HCl given byA. `10^(-6)+10^(-8)`B. `10^(-6)+10^(-7)`C. `10^(-6)`D. `10^(-6)-10^(-7)` |
Answer» Correct Answer - B |
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