pH of a mixture of HA and A^(-)buffer is 5. K_b of A^(-)=10 ^(-10 ) .Hence [HA]/ [A^(-) ] will be

pH of a mixture of HA and A^(-)buffer is 5. K_b of A^(-)=10 ^(-10 ) .H

1.	pH of a mixture of HA and A^(-)buffer is 5. K_b of A^(-)=10 ^(-10 ) .Hence [HA]/ [A^(-) ] will be
Answer» 1 10 `0.1` `100` SOLUTION :`pH =5 = pKa +log ""([S])/([A])` `pKa +PKB =14 rArr pKa =1 4 -10 =4` ` 5=4 +log ""([S])/([A]) rArr ([A^(-)])/([H_A]) =10`