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pH of a saturated solution of silver salt of monobasic acid HA is found to be 9. Find the K_(sp) of sparingly soluble salt Ag A(s). Given : K_(a)(HA)=10^(-10) Express your answer as a, b, c, d where K_(sp)=a.bxx10^(cd) [Written in scientific notation] |
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Answer» `{:(AgA(s)+H_(2)O(l)hArrHA(aq)+OH^(-)(aq)),(x-y""y""y):}` `K_(sp)=x(x-y)` `K_(H)=(K_(w))/(K_(a))=(y^(2))/((x-y))` `(10^(-10))/(10^(-10))=((10^(-5))^(2))/((x-y))` `x-y=10^(-6)` `x=10^(-5)+10^(-6)` `x=1.1xx10^(-5)` `K_(sp)=1.1xx10^(-5)xx10^(-6)` `K_(sp)=1.1xx10^(11)`Ans. |
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