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pH of an acidic buffer is given byA. `pH = pK_(a) +log.(["salt"])/(["acid"])`B. `pH = pK_(a) -log.(["salt"])/(["acid"])`C. `pH = (1)/(2)pK_(a) +log.(["salt"])/(["acid"])`D. `pH = log K_(a) +log.(["salt"])/(["acid"])` |
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Answer» Correct Answer - A By Henderson equation `pH = pK_(a) + log .(["salt"])/(["acid"])` |
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