1.

pH of aqueous solution of 0.1 M , NH_4Cl is found to be 5. The equilibrium constant for the neutralization of NH_4 OHby HCl is 10 ^(y) . The value of .y. is

Answer»


SOLUTION :` [H^(+) ]= SQRT(CKa)=10 ^(-5) ,K_a =(10^(-10))/( 10^(-1)) =10 ^(-9)`
` K_ N =(1)/(K_n)=(K_b)/(K_w)=(1)/(K_a)=(1)/(10^(-9) ) =10 ^(9) `


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