1.

pH of Ba(OH)_(2) Ssolution is 12. Its solubility product is :

Answer»

`10^(-6) M^(3) `
` 4 XX 10^(-6) M^(3)`
` 0.5 xx 10 ^(-7) M^(3)`
` 5xx 10 ^(-7) M^(3)`

Solution :`pH =12 RARR [OH^(-) ] =10 ^(_2)=2S rArr S =5 xx 10 ^(-3)`
` Ksp = 4S^(3) =5 xx 10 ^(-7) `


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