Phase difference between two waves y _(1) = A sin (omega t - kx) and y _(2)= A cos (omega t - kx)is ……

Phase difference between two waves y _(1) = A sin (omega t - kx) and y

1.	Phase difference between two waves y _(1) = A sin (omega t - kx) and y _(2)= A cos (omega t - kx)is ……
Answer» `pi/4` `pi` `pi/8` `pi/2` SOLUTION :`y _(1)=A sin (omega t - kx )` ` y _(2) = A cos (omega t - kx )` `therefore y _(2) = A sin ((pi)/(2) + omega t - kx)` `(because cos THETA = sin ((pi )/(2) + theta ))` Phase difference `= ((pi)/(2) + omega t - kx) - (omega t - kx)` br> `= (pi)/(2) + omega t - kx - omega t + kx` `=(pi)/(2) RAD`