1.

Photoelectric emission is observed from a metallic surface for frequenciesv_(1) and v_(2)of the incident light (v_(1)gtv_(2)).If the maximum values of kinetic energy of the photoelectrons emitted in the two cases are in the ratio 1:n,then the threshold frequency of the metallic surface is

Answer»

`(upsilon_2 - upsilon_1)/(K-1)`
`(Kupsilon_1 - upsilon_2)/(K-1)`
`(Kupsilon_2 - upsilon_1)/(K-1)`
`(upsilon_2 - upsilon_1)/(K)`

SOLUTION :`KE_1 , KE_2 = 1 :K, hupsilon_1 - hupsilon_0 = hupsilon_2 -hupsilon_0 = 1 :K`
`(hupsilon_1 - hupsilon_0)/(H upsilon_2 - hupsilon_0) = 1/KimpliesK (upsilon_1 - upsilon_2) = upsilon_2 - upsilon_0`
`impliesK upsilon_1 - K upsilon_0 = upsilon_2 - upsilon_0`
`impliesupsilon_0 (1-K) = upsilon_2 - K upsilon_1 impliesupsilon_0 = (upsilon_2 - K upsilon_1)/(1-K)`


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