Photoelectric emission is observed from a surface for frequencies v_(1) and v_(2) of the incident radiation (v_(1) gtt v_(2)). If the maximum kinetic energies of the photoelectrons in the two cases are in the ratio 1 : k, what will be the theshold frequency (v_(0)) in term of v_(1), v_(2) and k ?

Photoelectric emission is observed from a surface for frequencies v_(1

1.	Photoelectric emission is observed from a surface for frequencies v_(1) and v_(2) of the incident radiation (v_(1) gtt v_(2)). If the maximum kinetic energies of the photoelectrons in the two cases are in the ratio 1 : k, what will be the theshold frequency (v_(0)) in term of v_(1), v_(2) and k ?
Answer» SOLUTION :In 1st case, K.E. `= h v_(1) - h v_(0) = h (v_(1) - v_(0))` In 2nd case, K.E. `= h v_(2) - h v_(0) = h (v_(2) - v_(0))` GIVEN `(h (v_(1) - v_(0)))/(h(v_(2) - v_(0))) = (1)/(k) or v_(2) -v_(0) = k (v_(1) - v_(0)) = k v_(1) - kv_(0)` or `k v_(0) - v_(0) = kv_(1) - v_(2) or v_(0) (k -1) = kv_(1) = v_(2) or v_(0) = (kv_(1) - v_(2))/(k -1)`