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Photoelectrons are removed with kinetic energy `1.864 xx 10^(-21)J`, when photons of light with energy ` 4.23 xx 10^(-19) J` fall on the metal. What is the minimum energy required per mole to remove an electron potassium metal? Hing`: hv_(0)= hv-KE` Energy required per mole `=hv_(0) xx 6.022 xx 10^(23)` |
Answer» Correct Answer - `253.6 kJ mol^(-1)` | |