1.

Photons of energy `2.0eV` fall on a metal plate and release photoelectrons with a maximum velocity `V`. By decreasing `lambda` and `25%` the maximum velocity of photoelectrons is doubled. The work function of the metal of the material plate in `eV` is nearlyA. `2.22`B. `1.985`C. `2.35`D. `1.80`

Answer» Correct Answer - D
`1/2mv_(max)^(2)=hv-w` & `hv=(hc)/lambda`


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