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Physics Numerical :- starting from a stationary position, Rahul paddles his bicycle to attain a velocity of 6ms‐¹ in 30s. Then he applies brakes such that the velocity of the bicycle comes down to 4ms‐¹ in the next 5s. Calculate the acceleration of the bicycle in both the cases. All the best! ​

Answer»

first case :-Initial velocity ( U ) = 0Final velocity ( v ) = 6 ms‐¹Time ( t ) = 30 ssubstituting the given values of u, v and t :-a = ( 6 ms‐¹ – 0 ms‐¹ ) / 30 sa = 0.2 ms‐²In the second case :- Initial velocity ( u ) = 6 ms‐¹ Final velocity ( v ) = 4 ms‐¹Time ( t ) = 5 sThen, a = ( 4 ms‐¹ – 6 ms‐¹ ) / 5 sa = – 0.4 ms‐²The acceleration of the bicycle in the first case is 0.2 ms‐² and in the second case it is –0.4 ms‐².



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