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Pick out the incorrect statement for `XeF_(6)`A. ` XeF_(6)` is hydrolysed partially to form `XeOF_4`B. It reacts with `SiO_(2)` to form `XEOF_(4)`C. On complete hydrolysis, it forms `XeO_3`D. It acts as F acceptor when treated with alkali metal fluoride, but cannot act as F donor to form complexes. |
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Answer» Correct Answer - A It also act as `F^(-)` donor with covalent pentafluorides. `XeF_(6)+SbF_(5) to [XeF_(5)]^(+) [SbF_(6)]^(-)` (a) `XeF_(6)+H_(2)O to XeOF_(4)+2HF` `2XeF_(6)+SiO_(2) to 2XeOF_(4)+SiF_(4)` (c) `XeF_(6)+3H_(2)O to XeO_(3)+6HF` |
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