1.

Pick out the solution from the values given in the bracket next to each equation. show that the other values do not satisfy the equation.(a) 5m = 60 (10, 5, 12, 15)(b) n + 12 = 20 (12, 8, 20, 0)(c) p – 5 = 5 (0, 10, 5 – 5)(d) q/2 = 7 (7, 2, 10, 14)(e) r – 4 = 0 (4, -4, 8, 0)(f) x + 4 = 2 (-2, 9, 2, 4)

Answer»

(a) 5m = 60 (10, 5, 12, 15)

m = 12 a solution to the given equation because form = 12

5m = 5 × 12 = 60 and hence, the equation is satisfied

m = 10 is not a solution to the given equation because for m = 10.

5m = 5 × 10 = 50, and net 60

m = 5 is net a solution to the given equation because for m = 5,

5m = 5 × 5 = 25, and net 60

m = 15 is net a solution to the given equation because for m = 15

5m = 5 × 15 = 75, and net 6.

(b) n + 12 = 20 (12, 8, 20, 0)

n = 8 is a solution to the given equation because for n = 8

n + 12 = 8 + 12 = 20 and hence, the equation is satisfied

n +12 = 12 + 12 = 24, and net 20

n = 20 is net a solution to the given equation because for n = 20

n + 12 = 20 + 12 = 32, and net 20

(c) p – 5 = 5 (0, 10, 5 – 5)

p = 10 is a solution to the given equation because

for p = 10, p – 5 = 10 – 5 = 5 and hence, the equation is satisfied.

p = 0 is net a solution to the given equation because for p = 0 .

p – 5 = 5 – 5 = 0, and net 5

p = -5 is net s solution to the given equation because for p = -5
p = 5 = -5 – 5 = -10 and net 5

(d) q/2 = 7 (7, 2, 10, 14)

q = 14 is a solution to the given equation because for q = 7 (q/2) = 7/2 and not 7

q/2 = 7/2 and net 7

q = 2 is not a solution to the given equation because for q = 7

q/2  = 7/2 and net 7

q = 2 is net a solution to the given equation

because for q = 2

q/2 = 2/2 = 1, and net 7

q = 10 is net a solution to the given equation because for qn = 10,

q/2 = 10/2 = 5, and net 7

(e) r – 4 = 0 (4, -4, 8, 0)

r = 4 is a solution to the given equation because for

r = 4

r = 4 = 4 – 4 = 0 and hence, the equation is satisfied

r = -4 is net a solution to-the given equation because for r = -4

r – 4 = -4 – 4 = -8 and net 0

r = 8 is net a solution to the given equation because for r = 8

r – 4 = 8 – 4 = 4 and net 0

r = 0 is net a solution to the given equation because for r = 0

r – 4 = 0 – 4 = -4 and net 0 .

(f) x + 4 = 2 (-2, 9, 2, 4)

x = -2 is a solution to the given equation because for x – 2

x + 4 = -2 + 4 = 2 and hence, the equation is satisfied

x = 0 is net a solution to the given equation because for x = 0

x + 4 = 0 + 4 = 4 and net 2

x = 2 is net a solution to the given equation because for x = 2

x + 4 = 2 + 4 = 6 and net 2

x = 4 is net a solution to the given equation because for x = 4

x + 4 = 4 + 4 = 8, and net 2.



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