Place the last two terms of the following expressions in parentheses p

1.	Place the last two terms of the following expressions in parentheses preceded by a minus sign:(i) x + y – 3z + y (ii) 3x – 2y – 5z – 4(iii) 3a – 2b + 4c – 5(iv) 7a + 3b + 2c + 4(v) 2a2 – b2 – 3ab + 6(vi) a2 + b2 – c2 + ab – 3ac
Answer» (i) Given x + y – 3z + y x + y – 3z + y = x + y – (3z – y) (ii) Given 3x – 2y – 5z – 4 3x – 2y – 5z – 4 = 3x – 2y – (5z + 4) (iii) Given 3a – 2b + 4c – 5 3a – 2b + 4c – 5 = 3a – 2b – (–4c + 5) (iv) Given 7a + 3b + 2c + 4 7a + 3b + 2c + 4 = 7a + 3b – (–2c – 4) (v) Given 2a²– b² – 3ab + 6 2a²– b² – 3ab + 6 = 2a² – b² – (3ab – 6) (vi) Given a² + b² – c² + ab – 3ac a² + b² – c²+ ab – 3ac = a² + b² – c² – (- ab + 3ac)

Place the last two terms of the following expressions in parentheses preceded by a minus sign:(i) x + y – 3z + y (ii) 3x – 2y – 5z – 4(iii) 3a – 2b + 4c – 5(iv) 7a + 3b + 2c + 4(v) 2a2 – b2 – 3ab + 6(vi) a2 + b2 – c2 + ab – 3ac

Answer»

(i) Given x + y – 3z + y

x + y – 3z + y = x + y – (3z – y)

(ii) Given 3x – 2y – 5z – 4

3x – 2y – 5z – 4 = 3x – 2y – (5z + 4)

(iii) Given 3a – 2b + 4c – 5

3a – 2b + 4c – 5 = 3a – 2b – (–4c + 5)

(iv) Given 7a + 3b + 2c + 4

7a + 3b + 2c + 4 = 7a + 3b – (–2c – 4)

(v) Given 2a²– b² – 3ab + 6

2a²– b² – 3ab + 6 = 2a² – b² – (3ab – 6)

(vi) Given a² + b² – c² + ab – 3ac

a² + b² – c²+ ab – 3ac = a² + b² – c² – (- ab + 3ac)