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Please answer atleast ome question if you know I'll mark as brainliest please |
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Answer» Answer: Answer of question no. 26 is 2,9 and 16. Explanation: Let the three consecutive terms of the AP be a − d , a , and a + d . Given: Sum of these three terms is 27. Product of the terms is 288. ( a − d ) + a + ( a + d ) = 27 3 a = 27 a = 9 and ( a − d ) ( a ) ( a + d ) = 288 Now put the VALUE of 'a' in the above EQUATION we GET, ( 9 − d ) ( 9 ) ( 9 + d ) = 288 729 − 9 d 2 = 288 9 d 2 = 729 − 288 9 d 2 = 441 d 2 = 441 9 d 2 = 49 d = √ 49 d = 7 Therefore three consecutive terms are: ( 9 − 7 ) = 2 , ( 9 ) , and ( 9 + 7 ) = 16. Hence the three consecutive terms are: 2 , 9 , and 16 |
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