1.

Please answer atleast ome question if you know I'll mark as brainliest please​

Answer»

Answer:

Answer of question no. 26 is 2,9 and 16.

Explanation:

Let the three consecutive terms of the AP be

a

d

,

a

,

and

a

+

d

.

Given:

Sum of these three terms is 27.

Product of the terms is 288.

(

a

d

)

+

a

+

(

a

+

d

)

=

27

3

a

=

27

a

=

9

and

(

a

d

)

(

a

)

(

a

+

d

)

=

288

Now put the VALUE of 'a' in the above EQUATION we GET,

(

9

d

)

(

9

)

(

9

+

d

)

=

288

729

9

d

2

=

288

9

d

2

=

729

288

9

d

2

=

441

d

2

=

441

9

d

2

=

49

d

=

49

d

=

7

Therefore three consecutive terms are:

(

9

7

)

=

2

,

(

9

)

,

and

(

9

+

7

)

=

16.

Hence the three consecutive terms are:

2

,

9

,

and

16



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