InterviewSolution
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InterviewSolution
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Plot of log against log P is a straight line inclined at an angle of `45^(@)`. When the pressure is 0.5 atm and Freundlich parameter ,K is 10, the amount of solute adsorbed per gram of adsorbent will be : (log 5=0.6990 )A. 1 gB. 2 gC. 3 gD. 5 g. |
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Answer» Correct Answer - D `x//m=KP^(1//n)=10.0(0.5)=5` If m = 1g , then x=5g(given `1//n = tan theta =tan 45^(@)`=1) |
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