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Plot the corresponding SHM of particle. Indicate the intial (t=0) position of the particle, the radius of the circle and angular speed of the rotating particle. Consider sense of rotation to be anticlockwise and x in cm and tis in s. (b) x=cos((pi)/(6)-t) |
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Answer» Solution :`X=COS ((pi)/(6)-t)=1.cos [-(t-(pi)/(6))]=1.cos(t-(pi)/(6)).` `or x = cos (1.t-(pi)/(6))=cos(t+(11pi)/(6)).` Comparing this with `x=A cos (omegat+PHI)` we get, `A=1cm, OMEGA="1 rad s"^(1), phi=-(pi)/(6)" rad"{:("2pi-(pi)/(6)),((=11pi)/(6)):}`
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