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pls answer with full explanation.... |
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Answer» (i) solution According to question Width of sidewalk is x m Inner length of pool is (12- 2x) m Inner beadth of pool (7-2x) m Area of pool is 36 sq. m Area of pool =length × breadth 36= (12-2x) ×(7-2x) 36 = 84 - 24x -14x +4x^2 36= 84 -38x +4x^2 4x^2 -38x +48 = 0 2x^2 -19x + 24 = 0 is the required quadratic equation (ii) solution As we solve the above equation we will find the width of the sidewalk 2(2x^2 - 19x +24) = 0 2x^2 -19- + 24 = 0 2x^2 - 16x -3x +24 = 0 2x(x-8) -3(x-8) =0 (2x-3)(x-8) = 0 X = 3/2 or 8 Width of sidewalk = 8m is not possible Hence, width of sidewalk is 3/2 m I hope you will understand properly THANK YOU 1) 2x^ 2 -19x +24 = 0Is the required quadratic equation 2) And with of the sidewalk is 3/2 m |
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