Pls anwer my dears guys

1.	Pls anwer my dears guys
Answer» ANSWER: Case1: when the sheet is folded along its length : In this case, it forms a cylinder having height h1=18 cm and the circumference of its BASE equal to 30 cm. Let the radius of its base be r1. Then, 2pi r1=30 r1=15/pi. V1=pi r^2 H=pi(15/pi)^2 cm3=4050/pi.cm3 Case.2 When the sheet folded along its BREADTH : Heights h2=30cm and the circumference of its base equal to 18cm. Let the radius be r2. Then, 2pi r2=18=(9/pi) V2=pi r^2 h=(pi(9/11)^2) cm^3 =2430/pi cm^3. V1/v2=(4050/pi*pi/2430)=4050/2430=5/3 Ans.5:3.

Answer»

Case1: when the sheet is folded along its length :

In this case, it forms a cylinder having height h1=18 cm and the circumference of its BASE equal to 30 cm.

Let the radius of its base be r1. Then,

2pi r1=30

r1=15/pi.

V1=pi r^2 H=pi*(15/pi)^2 cm3=4050/pi.cm3

Case.2

When the sheet folded along its BREADTH :

Heights h2=30cm and the circumference of its base equal to 18cm.

Let the radius be r2. Then,

2pi r2=18=(9/pi)

V2=pi r^2 h=(pi*(9/11)^2) cm^3 =2430/pi cm^3.

V1/v2=(4050/pi*pi/2430)=4050/2430=5/3

Ans.5:3.

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