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Plss anwser me guys i am stuck again

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tion:Let the NUMBER be 1a,2a and 3a(1a)³ + (2a)³ + (3a)³ = 4500a³ + 8a³ + 27a³ = 450036a³ = 4500a³ = 4500/36a³ = 125a = 51A = 52a = 103a = 15So , the numbers are 5 , 10 and 15 Mark my ANSWER as a Brainliest



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