InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
PLZZ answer this friends: Area of the triangle formed by positive X-axis and the tangent and the normal at (1,root3) to the circle x^2+y^2=4??If anybody answer this with correct process then I surely mark as brainliest answer and give them 10 thanks |
| Answer» <html><body><p><strong>Answer:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of circle is given,</p><p>e.g., x² + y² = 4</p><p>we know, equation of tangent of circle x² + y² = C at (x₁,y₁) is given by xx₁ + yy₁ = C</p><p>so, equation of tangent through (1,√3) is</p><p>x + √3y = 4 -------(1)</p><p>=> y = 4/√3 - x/√3 , it cuts the axis at (4,0)</p><p></p><p>now, equation of <a href="https://interviewquestions.tuteehub.com/tag/normal-1123860" style="font-weight:bold;" target="_blank" title="Click to know more about NORMAL">NORMAL</a> to the circle is</p><p>(y - √3)= slope of normal (x - 1)</p><p></p><p>[ we know, slope of normal × slope of tangent = -1 so, slope of normal = -1/(-1/√3) = √3 {slope of tangent is -1/√3 as shown equation (1) ]</p><p></p><p>now, equation of normal is</p><p>(y - √3) = √3(y - 1)</p><p>=> y - √3 = √3x - √3</p><p>=> y = √3x -----(2)</p><p></p><p>for clearance , you should see attachment,</p><p>area formed by tangent, normal and x axis is</p><p></p><p></p><p>hence, answer is 2√3 sq unit</p><p></p><p></p><h2>hope it <a href="https://interviewquestions.tuteehub.com/tag/helps-1018140" style="font-weight:bold;" target="_blank" title="Click to know more about HELPS">HELPS</a> you..vote me..follow me..give ❤️ heart</h2><p></p><p></p><p></p></body></html> | |