Po(A) = 60 mm of Hg and Po(B) = 45mm of Hg. If 1 mol of A and 2 mol of B are mixed, the solution forms an azeotropic mixture with a minimum boiling point, then mole fraction of A in its vapour phase above the solution will be

Po(A) = 60 mm of Hg and Po(B) = 45mm of Hg. If 1 mol of A and 2 mol of

1.	Po(A) = 60 mm of Hg and Po(B) = 45mm of Hg. If 1 mol of A and 2 mol of B are mixed, the solution forms an azeotropic mixture with a minimum boiling point, then mole fraction of A in its vapour phase above the solution will be
Answer» $P_{(A)}^{o}$ = 60 mm of Hg and $P_{(B)}^{o}$ = 45mm of Hg. If 1 mol of A and 2 mol of B are mixed, the solution forms an azeotropic mixture with a minimum boiling point, then mole fraction of A in its vapour phase above the solution will be