InterviewSolution
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InterviewSolution
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Point `P(2, 4)` is translated through a distance `3sqrt2` units measured parallel to the line `y-x-1 = 0` in the directionof decreasing ordinates to reach at Q. If R is the imageof Q with respect to the line `y-x-1 = 0`, then thecoordinates of R are given by(1) `(5,7)`(2) `(-1,1)`(3) `(6,6)`(4) `(0,0)`A. (-1,1)B. (5,7)C. (6,6)D. (0,0) |
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Answer» The equation of a line through P( 2, 4) and parallel to y - x - 1 = 0 is `(x -2)/(cos pi //4) = (y-4)/(sin pi//4)` The coordinates of Q are given by gt `(x -2)/(cos pi //4) = (y-4)/(sin pi//4) = -3sqrt2 implies x = -1 , y = 1` Thus , the coordinates of Q are (-1,1). R is the image of Q with respect to the line y - x - 1 = 0 . Therefore , coordinate of R is given by `( x + 1)/(-1) = (y-1)/(1) = -2 ((1 + 1+ -1))/((-1)^(2) + (1)^(2))` `implies (x + 1)/(-1) = (y-1)/(1) = -1 implies x = 0 , y = 0 ` Hence , the coordinates of R are (0,0) . |
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