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Polynomial `P(x)` contains only terms of aodd degree. when `P(x)` is divided by `(x - 3)`, the ramainder is `6`. If `P(x)` is divided by `(x^(2) - 9)` then remainder is `g(x)`. Then find the value of `g(2)`. |
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Answer» Correct Answer - `4` As `P(x)` has only add degree terms `:. P(-x) = -P(x)` `rArr P(-3) = -P(3) = -6` Let `P(x) = Q(x^(2) - 9) + g(x)` where `Q` is quetient and `g(x)` is remainder `g(x) = ax + b` `P(x) = Q(x^(2)- 9) + ax + b` `x = 3, P(3) = 3a + b = 6 ….(i)` `x = -3, P(-3) = -3a + b = -6 ....(ii)` `b = 0` and `a = 2` `:. g(x) = 2x` `:. g(2) = 4` |
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