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Position of a body with acceleration `a` is given by `x=Ka^mt^n`, here t is time Find demension of m and n.A. `m=1`,`n=1`B. `m=1`,`n=2`C. `m=2`,`n=1`D. `m=2`,`n=2` |
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Answer» Correct Answer - B As `x=Ka^mxxt^n` `[M^0LT^0]=[LT^-2]^m[T]^n=[L^mT^(-2m+n)]` `m=1` and `-2m+n=0implies=n=2` |
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