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Position of a particle at any instant is given by `x = 3t^(2)+1` , where x is in m and t in sec. Its average velocity in the time interval `t = 2` sec to `t = 3` sec will be : |
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Answer» Correct Answer - 3 Position of …………… `t = 3 sec`. , `x = 3xx3^(2)+1= 28m` `t = 2sec`. , `x = 3xx2^(2)+1 = 13 m` Displacement `= 28 - 13 = 15m` `V_(avg) = (Delta x)/(Delta t) = (15m)/(1 sec) = 15m//sec`. |
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