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Position of a particle at any instant is given by `x = 3t^(2)+1` , where x is in m and t in sec. Its average velocity in the time interval `t = 2` sec to `t = 3` sec will be :A. `15 m//s`B. `12 m//s`C. `18 m//s`D. `6 m//s` |
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Answer» Correct Answer - A Position of ……….. `t = 3sec. x = 3xx3^(2)+1=28m` `t = 2sec. x =3xx2^(2)+1=13m` Diplacement `= 28 -13=15m` `V_(avg) = (Delta x)/(Delta t) = (15m)/(1sec) = 15 m//sec` |
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