Position vector of a particle is given as →r=⎛⎜⎝43 t32^i−t22^j+2t^k⎞⎟⎠m. Magnitude of acceleration at t=1 sec is:

Position vector of a particle is given as →r=⎛⎜⎝43 t32^i−t22

1.	Position vector of a particle is given as →r=⎛⎜⎝43 t32^i−t22^j+2t^k⎞⎟⎠m. Magnitude of acceleration at t=1 sec is:
Answer» Position vector of a particle is given as $\to r = ⎛ ⎜ ⎝ \frac{4}{3} t^{\frac{3}{2}}^i - \frac{t^{2}}{2}^j + 2 t^k ⎞ ⎟ ⎠ m$ . Magnitude of acceleration at $t = 1 sec$ is:

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Position vector of a particle is given as →r=⎛⎜⎝43 t32^i−t22^j+2t^k⎞⎟⎠m. Magnitude of acceleration at t=1 sec is:

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