Position vector of a particle moving in x−y plane at time t is →r=a(1−cosωt)^i+asinωt^j and the angular velocity of the particle is ωo^k. The magnitude of the linear velocity of particle at t=π2ω is

Position vector of a particle moving in x−y plane at time t is →r=

1.	Position vector of a particle moving in x−y plane at time t is →r=a(1−cosωt)^i+asinωt^j and the angular velocity of the particle is ωo^k. The magnitude of the linear velocity of particle at t=π2ω is
Answer» Position vector of a particle moving in $x - y$ plane at time $t$ is $\to r = a (1 - cos ω t)^i + a sin ω t^j$ and the angular velocity of the particle is $ω_{o}^k$ . The magnitude of the linear velocity of particle at $t = \frac{π}{2 ω}$ is

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Position vector of a particle moving in x−y plane at time t is →r=a(1−cosωt)^i+asinωt^j and the angular velocity of the particle is ωo^k. The magnitude of the linear velocity of particle at t=π2ω is

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