1.

Positive numbers x,y and z satisfy xyz=1081 and (log10x)(log10yz)+(log10y)(log10z)=468. Then the value of (log10x)2+(log10y)2+(log10z)2 is

Answer»

Positive numbers x,y and z satisfy
xyz=1081 and (log10x)(log10yz)+(log10y)(log10z)=468. Then the value of (log10x)2+(log10y)2+(log10z)2 is



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