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Potential energy of a particle executing SHM is assumed to be zero at equilibrium position then average KE of the particle is equal to: (where barv is average speed over one oscillation)

Answer» <html><body><p>average potential <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a>. <br/>`1/4 ma^ omega^2`<br/>`1/2 m v_(rms)^2`<br/>`1/2 m (<a href="https://interviewquestions.tuteehub.com/tag/barv-2461077" style="font-weight:bold;" target="_blank" title="Click to know more about BARV">BARV</a>)^2`</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::C</body></html>


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