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Potential energy of two equal negative point charges `2muC` each held 1 m apart in air isA. 2 JB. 2 eVC. 4 JD. 0.036 J |
Answer» Correct Answer - D `"As, PE"=(1)/(4pi epsilon_(0)).(q_(1)q_(2))/(r)=(9xx10^(9)(2xx10^(-6))^(2))/(1)=0.036J` |
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