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InterviewSolution
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Power `(P)` of a lens is given by reciprocal of focal length `(f)` of the lens. i.e. `P = 1//f`. When `f` is in metre, `P` is in dioptre. For a convex lens, power is positive and for a concave lens, power is negative. When a number of thin lenses of powers `p_(1), p_(2), p_(3)....` are held in contact with one another, the power of the combination is given by algebraic sum of the powers of all the lenses i.e., `P = p_(1) + p_(2) + p_(3) + ........` Answer the following questions : Focal length of the combined three lenses would beA. `-3.75 D`B. `0.5 D`C. `- 5 D`D. `1.25 D` |
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Answer» Correct Answer - A `P_2 = P - P_1 = (100)/(F) - (100)/(f_1)` `:. P_2 = (100)/(80)-(100)/(20) = 1.25 - 5 = -3.75 D`. |
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