InterviewSolution
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InterviewSolution
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PQTS and PTRQ are two parallelograms .show thatArea (△ PST ) = area ( △ PQT)Area (△ QTR ) =-area PQRS32ㄒ |
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Answer» GIVEN:parallelograms PSTQ and parallelogram PQRT.TO PROVE:ar(PST)=ar(QTR)=1/3*ar(PQRS)SOLUTION:ar(||gm PSTQ)=ar(||gm PQTR)•Since both the ||gms are on the same base and between the same ||'s. Now,In ||gm PQTSar(PTS)=ar(PQT)-1•diagonal of a ||gm dived it into 2 triangles.Similarly,In ||gm PQTRar(PQT)=ar(QRT) -2=> by 1 & 2ar(PTS)=ar(PQT)=ar(QTR)=ar(PQRS)ar(PTS)=1/3ar(PQRS)SO....ar(PTS)=ar(QTR)=1/3ar(PQRS) |
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