प्र.१ ला अ) दिलेल्या पर्याय�

1.	प्र.१ ला अ) दिलेल्या पर्यायांपैकी योग्य पर्याय निवडून विधाने पुन्हा लिहा.३) ६ ते १४ या वयोगटातील विद्यार्थ्यांना जे शिक्षण दिले जाते त्याला.......... शिक्षण म्हणतात.अ) उच्चब) प्राथमिकड) माध्यमिकशिक्षण म्हणतात.क) अंगणवाडी
Answer» $Correct Question:-ABC is a triangle, right angled at C. If AC = 7 cm AB = 25 cm find AB.\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf 7}\put(2.8,.3){\large\bf ?}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf C}\put(5.8,.3){\large\bf B}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\put(3.8,1.3){\large\bf $$}\end{picture}Answer:-We need to find out the value of Height.Concept:-Pythagoras TheoremLet's Do!We know that the Pythagoras theorem states that the sum of the square of base and height of a right angle triangle is equal to square of its hypotenuse.\sf{AC^2+CB^2=AB^2}AC 2 +CB 2 =AB 2 \sf{7^2+CB^2 = 25^2}7 2 +CB 2 =25 2 \sf{BC^2 = 625-49}BC 2 =625−49\sf{BC = 24 \ cm}BC=24 cmNote:-The question was completely dependant on the Pythagoras Theorem.hence, we should keep an eye on Prime factorisation and calculations also.Refer attachment if figure not visible.$

प्र.१ ला अ) दिलेल्या पर्यायांपैकी योग्य पर्याय निवडून विधाने पुन्हा लिहा.३) ६ ते १४ या वयोगटातील विद्यार्थ्यांना जे शिक्षण दिले जाते त्याला.......... शिक्षण म्हणतात.अ) उच्चब) प्राथमिकड) माध्यमिकशिक्षण म्हणतात.क) अंगणवाडी

Answer»

$Correct Question:-ABC is a triangle, right angled at C. If AC = 7 cm AB = 25 cm find AB.\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf 7}\put(2.8,.3){\large\bf ?}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf C}\put(5.8,.3){\large\bf B}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\put(3.8,1.3){\large\bf $$}\end{picture}Answer:-We need to find out the value of Height.Concept:-Pythagoras TheoremLet's Do!We know that the Pythagoras theorem states that the sum of the square of base and height of a right angle triangle is equal to square of its hypotenuse.\sf{AC^2+CB^2=AB^2}AC 2 +CB 2 =AB 2 \sf{7^2+CB^2 = 25^2}7 2 +CB 2 =25 2 \sf{BC^2 = 625-49}BC 2 =625−49\sf{BC = 24 \ cm}BC=24 cmNote:-The question was completely dependant on the Pythagoras Theorem.hence, we should keep an eye on Prime factorisation and calculations also.Refer attachment if figure not visible.$

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