InterviewSolution
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InterviewSolution
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Predict if there will be any precipitate by mixing 50 mL of 0.01 M NaCl and 50 mL of M `AgNO_(3)` solution. The solubility product of AgCl is `1.5xx10^(-10)`.A. Since ionic product is greater than solubility product no precipitate will be formed.B. Since ionic product is lesser than solubility product, precipitation will occur .C. Since ionic product is greater than solubility product, precipitation will occur.D. Since ionic product and solubility product are same, precipitation will not occur. |
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Answer» Correct Answer - C `NaCl+AgNO_(3)toAgCl+NaNO_(3)K_(sp)=1.5xx10^(-10)` `[Ag^(+)]=(1)/(2)xx10^(-2)M=0.5xx10^(-2)M` `[Cl^(-)]=(1)/(2)xx10^(-2)M=0.5xx10^(-2)M` `K_(ip)=[Ag^(+)][Cl^(-)]=(0.5xx10^(-2))xx(0.5xx10^(-2))=2.5xx10^(-5)K_(ip)gtK_(sp)` When `K_(ip)gtK_(sp)`, it results in precipitation. |
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