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Predict the formulas of the stable binary compounds that would be formed by the combination of the following pairs of elements. (a) Lithium and oxygen (b) Magnesium and nitrogen (c) Aluminium and iodine (d) Silicon and oxygen (e) Phosphorus and fluorine (f) Element 71 and fluorine |
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Answer» Solution :(a) LITHIUM belongs to group-1 with a valence of 1 while oxygen belongs to group-16 with a valence of 2. HENCE, the formula of the compound is `Li_(2)O`. (b) Magnesium belongs to group-2 with valence of 2 while nitrogen belongs to group-5 with a valence of 3. Hence, the formula of the compound `Mg_(3)N_(2)`. (C) Aluminium belongs to group-13 with a valence of 3 and IODINE belong to group-17 with valence of 1. Hence, the formula of the compound is `AlI_(3)`. (d)`SiO_(2) [:. "Silicon " 4^(TH) "valency in " 14^(th)"group valency is 4 and in " 16^(th) "group of oxygen having valency is " -2.]` (e)`PF_(5) "" [:. " In 15th group valency is 5 and flourine group 17th velency is"-1.]` (f) `71^(th)` elements means : `54 + 17 (4f^(14) 3d^(1) 6s^(2))`. Take elements E in `13^(th)` group having valency 3. Flourine `17^(th)` group having valency `-1` so formula is `EF_(3) " or " Z = 71` so, Formula : `LuF_(3)`. |
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