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| 1. |
Predict the number of unpaired electrons in the square planar `[Pt(CN)_4]^(2-)` ion. |
| Answer» For square planar shape, the hybridisation is `dsp^(2)`. Hence theunpaired electrons in 5d orbital pair up to make one d orbitalempty for `dsp^(2)` hybridisation. Thus there is no unpaired electron | |