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Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere, respectively. The ratio of their volumes is (1) 2 : 1 (2) 0.8 : 1 (3) 4 : 1 (4) 8 : 1 |
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Answer» (4) 8 : 1 P1 = P0 + 4T/r1 P2 = P0 + 4T/r2 r1 / r2 = 2 ⇒ V1 / V2 = 8 : 1 |
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