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pressure is 5× greater [email protected] surface. If the air pressure on surface of sea is 1.0×1.05 Pa, what depth has the diver reached in the sea? |
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Answer» \(P = \rho gh+P_0\\P=5P_0\\\rho = 1023.6\frac{kg}{m^3}\) Therefore: \(h = 4P_0/\rho g = \frac{4\cdot10^5}{1023.6\cdot 9.81}m \approx 39.83m\) |
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