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Pressure P, voluume V and temperature T for a certain gas are related by P = (AT - BT^(2))/(V) where A and B are constant. The work done by the gas as its temperature change from T_(1) to T_(2) with pressure remaining constant is |
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Answer» `A - (B)/(2)(T_(2) - T_(1))` Since P is a constant `:. PdV = (A-2BT)DT` As `dW = PdV = (A-2BT)dT :. W = underset(T_(1))overset(T_(2))int (A-2Bt)dT` `= [At - BT^(2)]_(T_(1))^(T_(2)) = A(T_(2) - T_(1)) - B(T_(2)^(2) - T_(1)^(2))` |
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