Probability density function of Normal Distribution.

1.	Probability density function of Normal Distribution.
Answer» \(f(x) = \frac{1}{\sqrt{σ2π}}e^{−\frac{1}2(\frac{x−μ}σ)^2} , -∞ < X < ∞\) Where, x = Value of normal variate X μ = Mean of normal distribution σ = Standard deviation of normal distribution π = Constant = 3.1416 e = Constant = 2.7183

Answer»

\(f(x) = \frac{1}{\sqrt{σ2π}}e^{−\frac{1}2(\frac{x−μ}σ)^2} , -∞ < X < ∞\)

Where, x = Value of normal variate X
μ = Mean of normal distribution
σ = Standard deviation of normal distribution
π = Constant = 3.1416
e = Constant = 2.7183

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