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probability for a contractor to get a road contract is 2/3 and to get a buildingis 5/9. The probability to get atleast one contract is 4/5. Find the probabilityt he gets both the contracts.A be the event of getting road contract and B be the event of getting building contractAP 1629OCONTRACTOR Qability that the contractor will get both the contracts is2 5 4 30+25-36 194545 |
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Answer» The probability of getting at least one contract [P(AUB)] is equal to the probability of getting an road contract [P(A)] plus the probability of getting the building contract [P(B)] minus the probability of getting both contracts [P(A∩B)]. In math symbols: P(AUB) = P(A) + P(B) - P(A∩B). So we can isolate P(A∩B). Add P(A∩B) to both sides and subtract P(AUB) from both sides. P(A∩B) = P(A) + P(B) - P(AUB) P(A∩B) = 5/9 + 2/3 - 4/5 convert to a common denominator of 45 P(A∩B) = 25/45 + 30/45 - 36/45 = 19/45 Like my answer if you find it useful! |
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